Probability with playing cards and Venn diagrams | Probability and Statistics | Khan Academy

Let’s do a little bit of
probability with playing cards.
And for the sake of
this video, we’re
going to assume that our
deck has no jokers in it.
You could do the same
problems with the joker,
you’ll just get slightly
different numbers.
So with that out of
the way, let’s first
how many cards we
have in a standard playing deck.
So you have four
suits, and the suits
are the spades, the diamonds,
the clubs, and the hearts.
You have four suits and
then in each of those suits
you have 13 different
types of cards–
and sometimes it’s
called the rank.

You have the ace, then you have
the two, the three, the four,
the five, the six,
seven, eight, nine, ten,
and then you have the Jack,
the King, and the Queen.
And that is 13 cards.
So for each suit
you can have any
of these– you can
have any of the suits.
So you could have a Jack of
diamonds, a Jack of clubs,
a Jack of spades,
or a Jack of hearts.
So if you just multiply
these two things–
you could take a deck of playing
cards, take out the jokers
and count them– but
if you just multiply
this you have four suits, each
of those suits have 13 types.
So you’re going to
have 4 times 13 cards,
or you’re going to have 52 cards
in a standard playing deck.
Another way you could
have said, look,
there’s 13 of these
ranks, or types,
and each of those come in four
different suits– 13 times 4.
Once again, you would
have gotten 52 cards.
Now, with that of
the way, let’s think
of different events.
So let’s say I
shuffle that deck.
I shuffle it really,
really well and then
I randomly pick a
card from that deck.
And I want to think about
what is the probability that I
pick a Jack.
Well, how many equally
likely events are there?
Well, I could pick any
one of those 52 cards.
So there’s 52 possibilities
for when I pick that card.
And how many of those 52
possibilities are Jacks?
Well you have the Jack of
spades, the Jack of diamonds,
the Jack of clubs, and
the Jack of hearts.
There’s four Jacks in that deck.
So it is 4 over 52– these
are both divisible by 4– 4
divided by 4 is 1, 52
divided by 4 is 13.
Now, let’s think
So I’ll start over.
I’m going to put that
Jack back and I’m
going to reshuffle the deck.
So once again, I
still have 52 cards.
So what’s the probability
that I get a hearts?
What’s the probability
that I just randomly pick
a card from a shuffled
deck and it is a heart?
Well, once again,
there’s 52 possible cards
I could pick from.
52 possible, equally likely
events that we’re dealing with.
And how many of those
have our hearts?
Well, essentially 13
of them are hearts.
For each of those suits
you have 13 types.
So there are 13
hearts in that deck.
There are 13 diamonds
in that deck.
There are 13 spades
in that deck.
There are 13 clubs in that deck.
So 13 of the 52 would result
in hearts, and both of these
are divisible by 13.
This is the same thing as 1/4.
One in four times
I will pick it out,
or I have a one in four
probability of getting a hearts
when I randomly pick a card
from that shuffled deck.
Now, let’s do something that’s
a little bit more interesting,
or maybe it’s a little obvious.
What’s the probability
that I pick something
that is a Jack– I’ll just
write J– and it is a hearts?

Well, if you are reasonably
familiar with cards
you’ll know that
there’s actually
only one card that is
both a Jack and a heart.
It is literally
the Jack of hearts.
So we’re saying, what
is the probability
that we pick the exact
card, the Jack of hearts?
Well, there’s only
one event, one card,
that meets this criteria
right over here,
and there’s 52 possible cards.
So there’s a one
in 52 chance that I
pick the Jack of hearts–
something that is both a Jack
and it’s a heart.
Now, let’s do something a
little bit more interesting.
What is the
probability– you might
want to pause this and think
before I give you the answer.
What is the probability
of– so I once again, I
have a deck of 52
cards, I shuffled it,
randomly pick a card from that
deck– what is the probability
that that card that I pick from
that deck is a Jack or a heart?
So it could be the
Jack of hearts,
or it could be the
Jack of diamonds,
or it could be the
or it could be the
Queen of hearts,
or it could be
the two of hearts.
So what is the
probability of this?
And this is a little bit
more of an interesting thing,
because we know, first
of all, that there
are 52 possibilities.
But how many of
those possibilities
meet these conditions that
it is a Jack or a heart.
And to understand that,
I’ll draw a Venn diagram.
Sounds kind of fancy,
but nothing fancy here.
So imagine that this
rectangle I’m drawing here
represents all of the outcomes.
So if you want, you could
imagine it has an area of 52.
So this is 52 possible outcomes.
Now, how many of those
outcomes result in a Jack?
So we already learned, one out
of 13 of those outcomes result
in a Jack.
So I could draw a
little circle here,
where that area– and I’m
approximating– represents
the probability of a Jack.
So it should be
roughly 1/13, or 4/52,
of this area right over here.
So I’ll just draw it like this.
So this right over here is
the probability of a Jack.

There’s four possible
cards out of the 52.
So that is 4/52,
or one out of 13.

Now, what’s the probability
of getting a hearts?
Well, I’ll draw another
little circle here
that represents that.
13 out of 52 cards
represent a heart.
And actually, one of those
represents both a heart
and a Jack.
So I’m actually going
to overlap them,
and hopefully this will
make sense in a second.
So there’s actually 13
cards that are a heart.
So this is the number of hearts.

And actually, let me write this
top thing that way as well.
It makes it a little bit
clearer that we’re actually
looking at the number of Jacks.

And of course,
this overlap right
here is the number of Jacks
and hearts– the number
of items out of this 52 that
are both a Jack and a heart–
it is in both sets here.
It is in this green circle and
it is in this orange circle.
So this right over here–
let me do that in yellow
since I did that problem in
yellow– this right over here
is a number of Jacks and hearts.
So let me draw a
little arrow there.
It’s getting a little
cluttered, maybe
I should draw a little
bit bigger number.

And that’s an
overlap over there.
So what is the probability
of getting a Jack or a heart?
So if you think about
it, the probability
is going to be the
number of events
that meet these conditions,
over the total number events.
We already know the total
number of events are 52.
But how many meet
these conditions?
So it’s going to be the
number– you could say,
well, look at the green
circle right there says
the number that gives us a Jack,
and the orange circle tells us
the number that
gives us a heart.
So you might want to say,
well, why don’t we add up
the green and the
orange, but if you
did that, you would
be double counting,
Because if you add
it up– if you just
did four plus 13–
what are we saying?
We’re saying that
there are four Jacks
and we’re saying that
there are 13 hearts.
But in both of these, when we
do it this way, in both cases
we are counting
the Jack of hearts.
We’re putting the
Jack of hearts here
and we’re putting the
Jack of hearts here.
So we’re counting
the Jack of hearts
twice, even though there’s
only one card there.
So you would have to subtract
out where they’re common.
You would have to
subtract out the item that
is both a Jack and a heart.
So you would subtract out a 1.
Another way to
think about it is,
you really want to figure
out the total area here.

And let me zoom in– and I’ll
generalize it a little bit.
So if you have one
circle like that,
and then you have another
overlapping circle like that,
and you wanted to figure
out the total area of both
of these circles
combined, you would
look at the area of this circle.

And then you could add it
to the area of this circle.
But when you do that, you’ll
see that when you add the two
areas, you’re counting
this area twice.
So in order to only
count that area once,
you have to subtract
that area from the sum.
So if this area has
A, this area is B,
and the intersection
where they overlap is C,
the combined area is
going to be A plus B– —
minus where they
overlap– minus C.
So that’s the same
thing over here,
we’re counting all
the Jacks, and that
includes the Jack of hearts.
We’re counting all
the hearts, and that
includes the Jack of hearts.
So we counted the
Jack of hearts twice,
so we have to subtract
1 out of that.
This is going to be
4 plus 13 minus 1,
or this is going to be 16/52.

And both of these things
are divisible by 4.
So this is going to be the
same thing as, divide 16 by 4,
you get 4.
52 divided by 4 is 13.
So there’s a 4/13 chance that
you’d get a Jack or a hearts.

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